CMAT Exam 2023 Shift 2 Solved Paper

A - 2 terms
B - 4 terms
C - 6 terms
$2+4+6+....2\mathrm{n}$ terms => this sum should be greater than or equal to 95 .
$2\left(1+2+3+...+\mathit{n}\right)\ge 95$
$\mathit{n}\left(\mathit{n}+1\right)\ge 95$
If $\mathit{n}=9$, we get only 90 terms.
95 th term occurs when $\mathit{n}=10$, i.e. $\mathit{J}$.
The answer is option C.