CMAT Exam 2023 Shift 2 Solved Paper

Sum is 24 : The only possibility is $\left(6,6,6,6\right)$⇒ 1 way
Sum is 23 : The only possibility is $\left(6,6,6,5\right)\Rightarrow \frac{4!}{3!}=4$ ways
Sum is 22 : There are two possibilities, i.e. $\left(6,6,6,4\right)$ and $\left(6,6,5,5\right)$

$\left(6,6,5,5\right)\Rightarrow \frac{4!}{2!2!}=6$ways
Total number of ways satisfying the given condition $=1+4+4+6=15$
Total number of possibilities $=\left(6\right)\left(6\right)\left(6\right)\left(6\right)$
Required probability $=\frac{15}{1296}=\frac{5}{432}$
The answer is option A.