CMAT Exam 2023 Shift 1 Solved Paper

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Question : 14 of 100

Marks: +1, -0

Average of

{\a}, {\b}

and

{\c}

is 11 ; average of

{\c}, {\d}

and

{\e}

is 17 ; average of

{\e}

and

{\f}

is 22 and average of

{\e}

and

{\c}

is 17 . What is the average of

a, b, c, d, e

and

f

?

$15 \;{2}/{3}$
$18 \;{1}/{2}$
$\;\; 16 \;{1}/{2}$
$16 \;{2}/{3}$

Solution:

It is given,

{a+b+c}/{3}=11

{\a}+ {\b}+ {\c}=33

.....(1)

{c+d+e}/{3}=17

{\c}+ {\d}+ {\e}=51

.......(2)

\;{e+f}/{2}=22

{\e}+ {\f}=44

.............(3)

\;{e+c}/{2}=17

{\e}+ {\c}=34

..............(4)

(1)+(2)+(3)-(4)

we get the sum of

a, b, c, d, e

and

f

\;a+b+c+d+e+f=(a+b+c)+(c+d+e)+(e+f)-(e+c)=33+51+44-34=94

\;\;\text " Average "\;=\;{94}/{6}=\;{47}/{3}=15 \;{2}/{3}

The answer is option A.

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