CMAT 2022 Solved Question Paper

It is given that $\frac{1}{\mathrm{x}}$ is positive and $\frac{1}{\mathrm{y}}$ is negative, this implies that $\mathrm{x}$ is positive and $\mathrm{y}$ is negative.
A) $\frac{1}{\mathrm{x}}+\frac{1}{\mathrm{y}}$ is positive, we know $\mathrm{x}$ is positive, and $\mathrm{y}$ is negative, but we cannot conclude which value is greater. Therefore, this may or may not be true.
B) $\frac{1}{\mathrm{x}}-\frac{1}{\mathrm{y}}$ is positive; we know that $\mathrm{mathrm}\mathit{x}$ is positive and $\mathrm{y}$ is negative. So this statement is definitely true.
(C) $\frac{\mathrm{x}-\mathrm{y}}{\mathrm{xy}}=-\left(\frac{1}{\mathrm{x}}-\frac{1}{\mathrm{y}}\right)$ As $\frac{1}{\mathrm{x}}-\frac{1}{\mathrm{y}}$ is positive and y is negative. Therefore, the statement is true.
D) $\mathrm{x}\mathrm{y}$ is negative as $\mathrm{x}$ is positive and $\mathrm{y}$ is negative. Therefore, the statement is false.
E) $\frac{1}{{\mathrm{x}}^2}-\frac{1}{{\mathrm{y}}^2}$ is positive only when ${\mathrm{y}}^2>{\mathrm{x}}^2$, but we cannot conclude which value is greater. Therefore, this may or may not be true.Only (B) and (C) are true.
Answer is option B