CMAT 2021 Solved Question Paper

Question : 5 of 100

Marks: +1, -0

How many ten-digit numbers can be formed using all the digits of 2435753228 such that odd digits appear only in even places?

$2 ! 3 ! 5 !$
$(5 !)^{2}$
${(5 !)^{2}}/{3 !}$
${(5 !)^{2}}/{3 !(2 !)^{2}}$

Validate

Solution:

We have number : 2435753228
We can write as 222 48 33557
We need to write ten digit numbers such that odd digits appear only in even places.
∴ Number of ways

={5 !}/{3 !} ×{5 !}/{2 ! 2 !}={(5 !)^{2}}/{3 !(2 !)^{2}}

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