CMAT 2017 Solved Question Paper

Given, x = OA = 4
AB is the diagonal of square, so it must be 4 x2 = 8
As diagonal of square = $\sqrt{2}$ a, where a is the side ofsquare.
Therefore, $\sqrt{2}$ a =8
⇒a = $\frac{8}{\sqrt{2}}=4\sqrt{2}$
Also, diameter of circle = side of square
⇒ d = 4$\sqrt{2}$
⇒ perimeter of circle = πd = 4$\sqrt{2}$ π