CMAT 2017 Solved Question Paper

(d) Thursday
26th January, 2012
Odd days upto 2000 =0
11 years ( 2 leap years + 9 ordinary years)
= (2x2 + 9x1) = 13 odd days
= 6 odd days
Total days from 1 to 26 January 2012 = 26 days = 5odd days.
Total odd days = (6 + 5) = 11 odd days
= $\frac{11}{7}$ = 4 odd days
4 odd days implies Thursday.