CMAT 2014 Solved Question Paper

${\mathit{P}}_1$ = Place of accident, Remaining distance = (x + 300) km
${\mathit{P}}_2$ = Imaginary place of accident, Remaining distance = x km
At point ${\mathit{P}}_1$ for distance (x + 300) km
Speed $\frac{1}{6}\downarrow$ Time $\frac{1}{5}\uparrow$
$\therefore$ Usual time required for distance $\left(\mathit{x}+300\right)\mathit{k}\mathit{m}=5\times 2=10\mathit{h}$
At point ${\mathit{P}}_2,$ for distance $\mathit{x}\mathit{k}\mathit{m}$
Speed $\frac{1}{6}\downarrow$ Time$\frac{1}{5}\uparrow =1\mathit{h}$
$\therefore$ Usual time required for distance $\mathit{x}\mathit{k}\mathit{m}=5\times 1=5\mathit{h}$
$\therefore$ Time required to cover $300\mathit{k}\mathit{m}=5\mathit{h}$
$\therefore$