CMAT 2013 Solved Question Paper

(c) Since, in the numerator of the product of the expression, there will be 2 zeroes at the end and these two zeroes will be cancelled by 2 zeroes of the denominator. Hence finally, we get a non-zero unit digit in the expression.
Now, $1\times 2\times 3\times 4$ × $\frac{5\times 6\times 7\times 8\times 9\times 10}{100}$
= $\frac{1\times 2^8\times 3^4\times 5^2\times 7^1}{5^2\times 2^2}$
= $1\times 2^6\times 3^4\times 7$
Therefore, the unit digit of the given expression will be same as that of = $1\times 2^6\times 3^4\times 7$
Multiplication is $1\times 2^6\times 3^4\times 7$ is ‘36288’.
Now, the unit digit is '8‘