CMAT 2013 Solved Question Paper

Question : 14 of 100

Marks: +1, -0

Two pipes A and B can fill a cistern in 15 h and 10 h respectively. A tap C can empty the full cistern in 30 h. All the three taps were open for 2 h, when it was remembered that emptying tap had been left open. It was then closed. How many hours more would it take for the cistern to be filled?

8 h 30 min
1.2 h
6 h 24 min
5 h 35 min

Validate

Solution:

100/16.66

Capacity filled in 2 h by pipes A, B and C = 2 x 13.33 = 26 66%
Remaining capacity = 73.33%
This remaining capacity can be filled by A and B =

73.33/16.66=4 2/5

h
So, the total time required = 2 + 4

2/5

h = 6 h 24 min
Thus, in this case 24 min extra are required.

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