CGPET 2022 Solved Paper

In VOSO4 oxidation state of vanadium is +4.
=[Ar]3d34s2
V4+=[Ar]3d14s0
Therefore, it is paramagnetic.
In K2Cr2O7 oxidation state of Cr=+6, unpaired electron =0
In (NH4)2[TiCl6] oxidation state of Ti=+4, unpaired electron =0
In K3[Cu(CN)4] oxidation state of Cu=+1, unpaired electron =0
In K2Cr2O7,(NH4)2[TiCl6] and K3[Cu(CN)4] in
coloured but diamagnetic but VOSO4 paramagnetic and coloured.