The slope of the tangent at (x, y) to a curve passing through (1, \frac{\pi}{4}) is given by \frac{y}{x}-\cos ^2 (\frac{y}{x}), then the equation of the curve is

Correct Answer is : y=xtan−1(log(ex))

y=x \tan ^{-1} (\log (\frac{x}{e}) )

y=x \tan ^{-1} (\log (\frac{e}{x}) )

y=x^2 \tan ^{-1} (\log (\frac{e}{x}) )

CGPET 2022 Solved Paper

Section: Mathematics

Question : 128 of 150

Marks: +1, -0

The slope of the tangent at (x,y) to a curve passing through (1,‌

) is given by ‌

−cos2(‌

), then the equation of the curve is

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