© examsiri.com
Question : 113 of 150
Marks:
+1,
-0
Solution:
We have,
F1=2−4+4,F2=2−3−6 ∴ Net force,
F=F1+F2 =(2−4+4)+(2−3−6) =4−7−2 Again,
PQ=OQ−OP =(10−2+2)−(4−2−6) =6+0+8 Now, work done
=F.PQ (4−7+2).(6−0+8) 24+0−16 8Units
© examsiri.com
Go to Question: