CGPET 2021 Solved Paper

The given circuit diagram is shown as

Heat produced in 5Ω resistance,
Qs=10cal∕s
∴ Q4=?
Since, potential difference between points A and B is same.
i.e. V=I1(R1+R2)‌and‌V=I2(R3)
⇒ I1(R1+R2)=I2R3
⇒

I1

I2

=

R3

R1+R2

=

5

4+6

⇒

I1

I2

=

5

10

=

1

2

∵

Q5

Q4

=

I2.2R3

I12R1

=

( 2 1 )2.5

4

⇒

10

Q4

=5
⇒ Q4=2cal∕s