CGPET 2021 Solved Paper

According to Einstein's photoelectric equation,
E=W0+Kmax .......(i)
where, W0= work - function,
Kmax= mximum kinetic energy of emitted electron
and E = energy of incident photon.
If v is the frequency of incident radiations, then
E=hv
hv=W0+Kmax [From eq. (i)]
⇒ Kmax=hv−w0
According to problem

K2−2K1=2‌hv−W0−hv+W0
K2−2K1=hv=E
∴ K2>2K1