CGPET 2021 Solved Paper

Digits 1,2,3,4,5
The total numbers formed by digits 1,2,3,4,5 is
=5!=120
Now, event A = Number formed by all digits 1,2,3,4,5 is divisible by 4

Last two digits can be 12,24,32,52
Number of favourable case =3!×4
∴ P(A)=

4×3!

5!

=

4

5×4

=

1

5