CGPET 2021 Solved Paper

In this circuit, the diode is connected in forward bias.

Hence, given circuit is redrawn as

Since, R2‌and‌R3 are in parallele, hence their equivalent resistance,
R′=

R2×R3

R2+R3

=

10×10

10+10

∴ R′=5kΩ
Now, i=

V

Rnet

=

30

10+5

=2A
Current through resistance R3,I3=i×RAB
=i×

R2

R2+R3

=2×

10

10+10

=1A
∴ Potential difference between points A and B,
VAB=I3R3=1×10=10V