CGPET 2019 Solved Paper

Given,
Current (i)=50×10−3 amp.
Time (t)=60min=3600sec
(F)=96500C
∵ charge (Q)=i×t
Q=i×t=50×10−3×3600=180C
Now, molar mass of copper (Cu)=63.5g and to convert to Cu(s)
∵96500C charge is required to deposit =63.5g of copper (s) and to convert Cu+→Cu(s) :
∵1C charge will deposit =

63.5

96500

gof Cu(s)
∴180C charge will deposit
=

63.5×180

96500

=0.118g of Cu
Hence, option (a) is the correct answer.