CGPET 2019 Solved Paper

Hybridisation of [Ni(CN)4]2 is calculated as follows
Hence, hybridisation of [Ni(CN)4]2 is dsp2 (due to the presence of strong field ligand)
Also, hybridisation of [Ni(NH3)6]2+ is shown as followsHence, hybridisation of [Ni(NH3)6]2− is sp3d2 [(NH3). is a weak field ligand ]
Thus, option (b) is the correct answer.