CGPET 2019 Solved Paper

Let the initial volume of gas =V1
Gas is compressed adiabatically then the volume.
V2=

V1

32

Initial temperature of gas =Ti (in kelvin)
Final temperature of gas =αTi
For diatomic gas, γ=

7

5

For adiabatic process,
⇒TVγ−1= constant
When initial volume is V1, then adiabatic process is given as
⇒TiV1γ−1= constant .......(i)
When volume is

1

32

of initial volume, then adiabatic process
∴αTi(

V1

32

)γ−1= constant .........(ii)
Now, Eqs. (i) and (ii), we get
or TiV1

7

5

−1=αTi(

V1

32

)

7

5

−1
or TiV1

2

5

=αTi(

V1

32

)

2

5

or 1=α(

1

32

)

2

5

α=(32)2∕5or α=4