CGPET 2019 Solved Paper

According to the question,Above circuit simplified as,The resistance between point C and F are connected in parallel combination. Hence, its equivalent resistance is given by

1

RCF

=

1

1

+

1

1

+

1

1

⇒RCF=

1

3

Ω
Now, circuit becomes
All the resistance in the above circuit are connected in the series combination.
Hence, RAB=1+1+

1

3

=2+

1

3

=2

1

3

Ω