CGPET 2019 Solved Paper

Given,
Magnitude of electric field intensity =E
Hence, the electric force on electron, F=qE ....... (i)
Weight of electron, w=mg
where, m= mass of electron and
g= gravitational acceleration.
According to the question, Electrical force = weight of electron
qE=mg⇒E=

mg

q

Here, charge on electron, q=e
E=

mg

e