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CGPET 2019 Solved Paper
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Section:
Mathematics
© examsiri.com
Question :
149 of 150
Marks:
+1
,
-0
If
u
=
^
i
×
(
a
×
^
i
)
+
^
j
×
(
a
×
^
j
)
+
^
k
×
(
a
×
^
k
)
,then
u
=
0
u
=
^
i
+
^
j
+
^
k
u
=
2
a
u
=
a
Validate
Solution:
Let,
a
=
x
^
i
+
y
^
j
+
z
^
k
∵
^
i
×
^
i
=
0
^
i
×
^
k
=
−
^
j
^
i
×
^
j
=
^
k
Similarly for
^
j
and
^
k
u
=
^
i
×
(
a
×
^
i
)
+
^
j
×
(
a
×
^
j
)
+
^
k
×
(
a
×
^
k
)
=
^
i
×
(
−
y
^
k
+
z
^
j
)
+
^
j
×
(
x
^
k
+
−
z
^
i
)
+
^
k
×
(
−
x
^
j
+
y
^
i
)
=
y
^
j
+
z
^
k
+
x
^
i
+
z
^
k
+
x
^
i
+
y
^
k
=
2
(
x
^
i
+
y
^
j
+
z
^
k
)
=
2
a
© examsiri.com
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