The solution of the differential equation (1+y^{2})+(x-e^{\tan ^{-1} y}) \frac{d y}{d x}=0 is

Correct Answer is : 2xetan−1y=e2tan−1y+k

2 x e^{\tan ^{-1} y}=e^{2 \tan ^{-1} y}+k

2 x e^{\tan ^{-1} y}=e^{\tan ^{-1} y}+k

x e^{\tan ^{-1} y}=e^{\tan ^{-1} y}+k

x e^{\tan ^{-1} y}=3 e^{\tan ^{-1} y}+k

CGPET 2019 Solved Paper

Section: Mathematics

Question : 117 of 150

Marks: +1, -0

The solution of the differential equation
(1+y2)+(x−etan−1y)

=0 is

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