CGPET 2019 Solved Paper

The general equation of parabola whose axes are parallel to Y -axis.
y=ax2+bx+c ........(i)
Differentiate w.r to 'x', we get

dy

dx

=2ax+b
Again, differentiate. W.r. to 'x', we get

d2y

dx2

=2a
And again, differentiate. W.r to 'x', we get

d3y

dx3

=0
This is required differential equation.
The order of this equation is 3.