If f(x)=|x|^{|\sin x|}, then f'(-\frac{\\pi}{6}) is equal to

Correct Answer is : √π6(−√32logπ6−3π)

\\sqrt{\frac{\\pi}{6}}(-{\\sqrt{3}/{2} \log \frac{\\pi}{6}+\frac{3}{\\pi})

\\sqrt{\frac{\\pi}{6}}(-{\\sqrt{3}/{2} \log \frac{\\pi}{6}-\frac{3}{\\pi})

\\sqrt{\frac{\\pi}{6}}( {\\sqrt{3}/{2} \log \frac{\\pi}{6}-\frac{3}{\\pi})

CGPET 2019 Solved Paper

Section: Mathematics

Question : 107 of 150

Marks: +1, -0

If f(x)=|x||sin‌x|, then f′(−

) is equal to

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