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Question : 146 of 150
Marks:
+1,
-0
Solution:
Given, ∫ex.(1+tan‌x).sec‌x‌d‌x
∫ex.sec‌x‌d‌x +∫ex.tan‌x.sec‌x‌d‌x
=ex.sec‌x−∫ex.sec‌x.tan‌x‌d‌x +∫ex.sec‌x.tan‌x‌d‌x
=ex‌sec‌x+C
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