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Question : 137 of 150
Marks:
+1,
-0
Solution:
Given,
A=−6+10 ,
B=−−3+7, C=5−7+λ, D=7−4+7 Then,
==−2+3−3 ==4−+(λ−10) ==6+2−3 ∴ Volume of tetrahedron
=[] ∴11=|| −2 | 3 | −3 |
| 4 | −1 | (λ−10) |
| 6 | 2 | −3 |
| ⇒11=[−2{3−2(λ−10)}−3(−12−6 (λ−10))−3(8+6)] ⇒11=[−2{23−2λ} −3(48−6λ)−48] ⇒66=[−46+4λ−144 +18λ−48] ⇒66=[−238+22λ] ⇒22λ=304 ⇒λ== unit
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