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Question : 95 of 150
Marks:
+1,
-0
Solution:
Given, Mass of
H2SO4(w)=4.9g Volume of solution
(V)=100mL Molar mass
(M)=98 Molarity
(C)=, ∴C=× Molarity
=0.5mol∕L⇒0.5M Normality (
)=Z× molarity
(C) Where,
Z= equivalent factor
For
H2SO4(Z=2)⇒0.5M ∴ Normality
=2×0.5=1N
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