CGPET 2017 Solved Paper

The wavelength of light emitted by the star =5896Å
λ=5896×10−10m Speed v=3600km∕s=3600×103m∕s
From Doppler's law in light shift in wavelength
Δλ=

v

C

.λ(c=3×108m∕s, speed of light)
=

3600×103×5896×10−10

3×108

m
=

12×5896×10−10

103

Δλ=70.752Å
The wavelength of light observed on each will increase by 70.75Å