A drop of solution (volume 0.05 {\mL} ) contains 3 \times 10^{-6} mole {\H}^{+}. If the rate constant of disappearance of {\H}^{+}is 1.0 \times 10^7 {\mol} {\L}^{-1} { s}^{-1}, how long would it take for {\H}^{+}in drop to disappear?

Correct Answer is : 6×10−9 s

CGPET 2016 Solved Paper

Section: Chemistry

Question : 84 of 150

Marks: +1, -0

A drop of solution (volume 0.05‌mL ) contains 3×10−6 mole H+. If the rate constant of disappearance of H+is 1.0×107‌mol‌L−1‌ s−1, how long would it take for H+in drop to disappear?

4×10−6 s
1×10−7 s
3×10−6 s
6×10−9 s

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