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Question : 110 of 150
Marks:
+1,
-0
Solution:
Given lines are
== and
== ∴ Shortest distance is given by
d=| [] |
| √(15−16)2+(12−10)2+(8−9)2 |
= ⇒
d=| 1(15−16)−2(10−12)+8−9) |
| √6 |
== ∴
[d]=0
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