CGPET 2015 Solved Paper

Given equation of circles are
x2+y2=4
and x2+y2−8x+12=0
or x2+y2=(2)2 ...(i)
(x−4)2+(y−0)2=(2)2 ...(ii)
The figure of both the circle are shown below :

Fromfigure, we see that there is exactly three common tangents.