What is the direction of the electric field at the centre O of the square in the figure shown below? Given that, q=10‌nC and the side of the square is 5‌cm.
‌=14.4‌ along ‌OA Resultant of EA and ED,E1=(14.4−7.2) =7.2NC−1 along OA. Resultant of EB and EC,E2=(14.4−7.2) =7.2NC−1 along OB. Since, E1 and E2 are perpendicular to each other. ∴E=√E12+E22 is along 45∘ to OA upward.