© examsiri.com
Question : 124 of 150
Marks:
+1,
-0
Solution:
Given equation of line is
lx+my+n=0 and equation of ellipse is
‌+‌=1.
∴ The equation of any normal to the ellipse is
5x secθ−3y‌cosec‌θ=25−9 (| ∵‌ the equation of any normal to the ellipse ‌ |
| ‌+‌=1‌ is ‌ax secθ−by‌cosec‌θ=a2−b2 |
) ⇒‌‌5x secθ−3y‌cosec‌θ−16=0As the Eq. (i) is the normal to the ellipse.
‌∴‌‌‌=‌=‌‌⇒cos‌θ=‌‌‌‌ and ‌sin‌θ=‌‌∵‌‌cos2θ+sin‌2θ=1‌∴‌‌(‌)2+(‌)2=1⇒‌‌‌+‌=1⇒‌‌‌+‌=‌
© examsiri.com
Go to Question: