The work done in increasing the size of a rectangular soap film with dimensions 8 {\cm} \times 3.75 {\cm} to 10 {\cm} \times 6 {\cm} is 2 \times 10^{-4} {\J}. The surface tension of the film in {\N} {\m}^{-1} is

Correct Answer is : 3.3×10−2

CGPET 2014 Solved Paper

Section: Physics

Question : 1 of 150

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The work done in increasing the size of a rectangular soap film with dimensions 8‌cm×3.75‌cm to 10‌cm×6‌cm is 2×10−4J. The surface tension of the film in Nm−1 is

3.3×10−2
1.65×10−2
8.25×10−2
6.6×10−2

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