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Question : 129 of 150
Marks:
+1,
-0
Solution:
Let
I=‌‌dx . . . (i)
‌⇒I=‌| √2+3−x |
| √2+3−(5−x)+√2+3−x |
‌dx‌⇒I=‌‌dx . . . (ii)
Adding Eqs. (i) and (ii), we get
2I‌=(‌| √x+√5−x |
| √x+√5−x |
)‌dx‌=1‌dx=[x]23=1 ⇒‌‌I=‌
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