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Question : 123 of 150
Marks:
+1,
-0
Solution:
Given function
sin‌−1(‌)At
x=1,LHL‌sin‌−1[‌]‌=sin‌−1(‌)=‌and RHL
‌sin‌−1[‌]‌=sin‌−1(‌)=‌and
f(1)=sin‌−1(‌)=‌Thus, given function is continuous at
x=1.
Now,
‌{sin‌−1(‌)}=‌⋅[‌] ‌=‌⋅‌‌=‌| 2x2−1 |
| √−(1+x4−2x2)⋅(2x) |
‌=‌which does not exist at
x=1.
Hence, given function is not differentiable at
x=1.
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