CDS Model Paper 4 Mathematics

Construction : In quadrilateral ABCD, from A to C.
Now, in ΔABC∵ AB=BC....(Given)
∴ ∠BAC= ∠BCA (angles opposite to equal side)
In ΔADC,
∵ CD>AD
∴ ∠DAC> ∠DCA
(since in a triangle, angle opposite to greater side is bigger than the angle opposite to smaller side)
On adding eqs. (l) and (ii), we get
∠BAD> ∠BCD