CDS Model Paper 3 Mathematics

Here H×30=4×30=120°.
(Since initially the hour hand is at 4.∴H=4 ).
Required angle A=90° and since, H×30>A°‌so, there will be two timings.
Required time T=

2

11

(H×30±A) minutes past H.
∴ One timing =

2

11

(4×30+90) minutes past 4
=38

2

11

minutes past 4
Ог 4:38 approx.