CDS Model Paper 2 Mathematics

Let the cost of one chair =₹x
Cost of one table =₹y
According to question,
10x+6y=6200 ...(i)
and 3x+2y=1900 ...(ii)
⇒ 9x+6y=5700 ...(iii)
On subtracting equation (iii) from equation (i), we get 10x+6y=6200
⇒ −9x+6y=5700
⇒ x=500
∴ x=₹500
From equation (i),
5000+6y=6200
⇒ 6y=1200
⇒ y=₹200
∴ Cost of 4 chairs and 5 tables =4x+5y
=4×500+5×200
=2000+1000=₹3000