CAT Exam Model Paper 6 with solutions for free online practice

Let the number N be $\prime 6\times {10}^{4+\mathit{p}}+\mathit{k}\prime$ where p is awhole number and k is some natural number.
According to the information given:
$6\times {10}^{4+\mathit{p}}+\mathit{k}=25\left(6\times {10}^{4+\mathit{p}}+\mathit{k}-6\times {10}^{4+\mathit{p}}\right)$= 25k
⇒ 24k = 6 x 10${}^{4+\mathit{P}}$
⇒ k = 2500 x 10 ${}^{\mathit{p}}$
So N = 62500 x 10${}^{\mathit{p}}$.
Sum of the digits of N = 13.