CAT Exam Model Paper 5 with solutions for free online practice

We can see that the difference between the divisor and the respective remainder is the same in each division i.e. $2-1=4-3=6-5=8-7=1$
Hence the general form of such numbers will beLCM(2, 4, 6 and 8).$\mathit{K}-1=24\mathit{K}-1,$ where ‘K’ is anynatural number.
Hence the numbers are 23, $23+24,23+2\times 24,......23+40\times 24$
A total of 41 such numbers are there between 0 and 1000.