CAT Exam Model Paper 3 with solutions for free online practice

Question : 88 of 100

Marks: +1, -0

Let a,b,c distinct digits. Consider a two-digit number ‘ab’ and a three-digit number ‘ccb’, both defined under the usual decimal system, If (ab)

^{2}

= ccb >300, then find the value of b.

Solution:

(ab)

^{2}

= ccb , the greatest possible value of ‘ab ’ to be 31. Since

31^2

= 961and since ccb > 300, 300 < ccb < 961, so 18 < ab < 31.
So the possible value of ab which statisfies (ab)

^{2}=

ccb is 21. So

21^2=441

∴ a = 2, b = 1, c = 4

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