CAT Exam Model Paper 1 with solutions for free online practice

Question : 69 of 100

Marks: +1, -0

The ratio of water and alcohol in two different containers is 2:3 and 4:5. In what ratio we are required to mix the mixtures of two containers in order to get the new mixture in which the ratio of alcohol and water be 7:5?

7: 3
5: 3
8: 5
2: 7

Validate

Solution:

(b)

\W_{1}: \A_{1}

2:3

{ \W _ { 1 } } /{ \W _ { 1 } + \A _ { 1 } } = { 2 } /{ 5 }

= { 72 } /{ 180 }

\W _ { 2 } :\A _ { 2 } = 4 : 5

{ \W _ { 2 } } /{ \W _ { 2 } + \A _ { 2 } }

= { 4 } /{ 9 } = { 80 } /{ 180 }

\W _ { \N } : \A _ { \N } =5 : 7

{ \W _ { \N } }/ { \W _ { \N } + \A _ { \N } }

= { 5 }/ { 12 } = { 75 } /{ 180 }

Therefore, the ratio is 5: 3.

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