CAT Exam 2021 Slot 1 Solved Paper

Let the cost of an apple, an orange and a mango be a, o, and m respectively.
Then it is given that:
$2\mathit{a}+4\mathit{o}+6\mathit{m}=\mathit{a}+4\mathit{o}+8\mathit{m}$
or $\mathit{a}=2\mathit{m}$
Also,$\mathit{a}+4\mathit{o}+8\mathit{m}=8\mathit{o}+7\mathit{m}$
$10\mathit{m}-7\mathit{m}=4\mathit{o}$
$3\mathit{m}=4\mathit{o}$
We can now express the cost of a basket in terms of mangoes only:
$2\mathit{a}+4\mathit{o}+6\mathit{m}=4\mathit{m}+3\mathit{m}+6\mathit{m}=13\mathit{m}$