CAT 2023 Slot 2 Solved Paper

Let the number of total employees in the company be $100\mathit{x}$, and the total salary of all the employees be $100\mathit{y}$.
It is given that $20\%$ of the employees work in the manufacturing department, and the total salary obtained by all the manufacturing employees is one-sixth of the total salary obtained by all the employees in the company.
Hence, the total number of employees in the manufacturing department is $20\mathit{x}$, and the total salary received by them is $\left(100\mathit{y}∕6\right)$
Average salary in the manufacturing department $=\left(100\mathit{y}∕6*20\mathit{x}\right)=5\mathit{y}∕6\mathit{x}$
Similarly, the total number of employees in the nonmanufacturing department is $80\mathit{x}$, and the total salary received by them is $\left(500\mathit{y}∕6\right)$
Hence, the average salary in the nonmanufacturing department $=\left(500\mathit{y}∕6*80\mathit{x}\right)=25\mathit{y}∕24\mathit{x}$
Hence, the ratio is:- $\left(5\mathit{y}∕6\mathit{x}\right)$ : $\left(25\mathit{y}∕24\mathit{x}\right)$
$\Rightarrow 120:150=4:5$
The correct option is B