CAT 2023 Slot 2 Solved Paper

Let the total score of day 1 , day 2 , day 3 , day 4 , and day 5 are $\mathrm{d}1,\mathrm{d}2,\mathrm{d}3,\mathrm{d}4$, and $\mathrm{d}5$, respectively.
The table shows that $\mathit{d}1+\mathit{d}2=30...$ eq (1), $\mathit{d}2+\mathit{d}3=31...$ eq ( 2 ), $\mathit{d}3+\mathit{d}4=32...$. eq(3), $\mathit{d}4+\mathit{d}5=34...$ eq(4)
It is given that participants are ranked each day, with the person having the maximum score being awarded the minimum rank (1) on that day. All participants with a tied score are awarded the best available rank if there is a tie.
It is given that the total score on Day 3 is the same as the total score on Day 4.
Therefore, $\mathrm{d}3=\mathrm{d}4\Rightarrow \mathrm{d}3=\mathrm{d}4=16$, which implies $\mathrm{d}2=15,\mathrm{d}5=18$, and $\mathrm{d}1=15$.
The day-wise score is given below: It is known that Chatur always scores in multiples of 3 . His score on Day 2 is the unique highest score in the competition. His minimum score is observed only on Day 1, and it matches Akhil's score on Day 4.
Hence, only Chatur scored 9 (one time) on Day 2, and no other person scored 9 on any of the given 5 days. Chatur scored 3 only one time, which was on Day 1 . Therefore, the scores obtained by Chatur on Day 3, Day 4, and Day 5 are 6, 6, and 6, respectively. It is also known that Akhil's score on Day 4 is the same as the score obtained by Chatur on Day 1. Hence, Akhil's score on Day 4 is 3.
Hence, we get the following table:From Table 2, we see that the rank of Bimal and Akhil is the same, which is 2 . Hence, The score obtained by Akhil and Bimal is the same. Let the score be $\mathit{x}$. Therefore, $6+2\mathit{x}=16\Rightarrow \mathit{x}=5$
The rank of Chatur on Day 5 is 2, and the rank of Bimal is 1, which implies the score obtained by Bimal will be more than Chatur. Hence, Bimal can score either 7 or 8 on Day 5. Therefore, the score obtained by Akhil on Day 5 is either 5 or 4 .It is given that Bimal's scores are the same on Day 1 and Day 3 . Hence, the score obtained by Bimal on Day 1 is 5, which implies The score obtained by Akhil is 7 on Day 1.
From Table 2, we can see that the rank of Bimal is 3 on Day 2, and the rank of Akhil is 2 on Day 2. Hence, the score of Bimal will be lower than Akhil on Day 2.
Let the score of Akhil be $\mathrm{a}$, and the score of Bimal be $\mathrm{b}$. Then $9+\mathrm{a}+\mathrm{b}=15$, and $\mathrm{a}>\mathrm{b}$

Hence, the value of a can be $4∕5$, and the value of $\mathit{b}$ can be $2∕1$
Therefore, the final table is given below:In the question, it is given that the score obtained by Akhil is 24, which implies the score obtained by Bimal is 26