CAT 2022 Slot 3 Paper

Let the unit of work done by 1 man in 1 hour and 1 day be $1\mathrm{MDH}$ unit (Man Day Hour).
Thus, in 7 hours per day for 10 days, the work done by $\mathrm{N}$ people $=\mathrm{N}\times 7\times$ $10\mathrm{MDH}$ units.
Since this is equal to $35\%$ of the total work,
$35\%$ of the total work $=\mathrm{N}\times 7\times 10\mathrm{MDH}$ units.
Total work $=\frac{\left(\mathrm{N}\times 100\times 7\times 10\right)}{35}=200\times \mathrm{N}$ MDH units.
The work left $=200\mathrm{N}-70\mathrm{N}=130\mathrm{N}$ MDH units.
Now, 10 people left the job. So, the number of people left $=\left(\mathrm{N}-10\right)$
Since $\left(\mathrm{N}-10\right)$ people completed the rest of work in 14 days by working 10 hours a day,
$\left(\mathrm{N}-10\right)\times 14\times 10=130\mathrm{N}$
$10\mathrm{N}=1400$
$\mathrm{N}=140$
Thus, the correct option is $\mathrm{D}$.