CAT 2022 Slot 1 Paper

In a parallelogram, two diagonals of parallelogram bisects each other, which concludes that mid-point of both diagonals are the same.
Midpoint of $\mathrm{AC}=\left(\frac{1-2}{2},\frac{1+8}{2}\right)$
Let the coordinates of vertex $\mathrm{D}$ be $\left(\mathit{x},\mathit{y}\right)$
$\left(\frac{\mathit{x}+3}{2},\frac{\mathit{y}+4}{2}\right)=\left(\frac{1-2}{2},\frac{1+8}{2}\right)$
$\mathit{x}=-4$ and $\mathit{y}=5$
The answer is option D.